Use Elimination to solve a + c = 327 and 4a + 1.50c = 978
By Andrew Mccoy
Use the elimination method to solve:
a + c = 327
4a + 1.50c = 978
Check Format
Equation 1 is in the correct format.
Check Format
Equation 2 is in the correct format.
Step 1: Multiply Equation 1 by 4:
4 * (a+c=327) --> 4a + 4c = 1308
Step 2: Multiply Equation 2 by 1:
1 * (4a+1.50c=978) --> 4a + 1.5c = 978
Step 3: Equation 1 - Equation 2:
4a + 4c = 1308 - (4a + 1.5c = 978)
-(4a + 1.5c = 978)
4c - 1.5c = 1308 - 978
Step 4: simplify and solve for c:
2.5c = 330
| c = | 330 |
| 2.5 |
c = 132
Step 5: Rearrange Equation 1 to solve for a:
1a = 327 - 1c
Divide each side by 1
| a = | 327 - 1c |
| 1 |
Step 6: Plug c = 132 into equation 1:
| a = | 327 - 1(132) |
| 1 |
| a = | 327 - 132 |
| 1 |
| a = | 195 |
| 1 |
a = 195
What is the Answer?
How does the Simultaneous Equations Calculator work?
Free Simultaneous Equations Calculator - Solves a system of simultaneous equations with 2 unknowns using the following 3 methods:
1) Substitution Method (Direct Substitution)
2) Elimination Method
3) Cramers Method or Cramers Rule
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2 equations 2 unknowns
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What 1 formula is used for the Simultaneous Equations Calculator?
What 7 concepts are covered in the Simultaneous Equations Calculator?
- cramers rule
- an explicit formula for the solution of a system of linear equations with as many equations as unknowns
- eliminate
- to remove, to get rid of or put an end to
- equation
- a statement declaring two mathematical expressions are equal
- simultaneous equations
- two or more algebraic equations that share variables
- substitute
- to put in the place of another. To replace one value with another
- unknown
- a number or value we do not know
- variable
- Alphabetic character representing a number
